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Proof step 19 from proof prepost-init-vols-mappings (previous step)

# wlar = # apebs, wlar[n0] = wl-entry(m4, stat), apebs[n0] = mkpeb(aehdr0, avhdr0, buf0, m1, boolvar0), apebs[n] = mkpeb(aehdr, avhdr, buf, m, boolvar), recs0[v × m0] = recovery-entry(n0, m3), bflipset-cons(bflipset, wlar), unique-sqns(apebs), unmapped-vols(vols), valid-eraseq(wlar, q), valid-eraseq-stronger(apebs, q), valid-vtbl(apebs, vols, wlar, n), valid-wl(apebs, wlar), v × m0 ∈ recs0, ∀ ladr, m. ladr ∈ recs0 ∧ recs0[ladr].pnum = m ↔ wlar[m].status = used ∧ m < # apebs ∧ apebs[m].vidhdr.vol = ladr.vol ∧ apebs[m].vidhdr.leb = ladr.leb ⊦ v × m0 = VTBL_VOLID × VTBL_LNUM, n0 ∈ q, n ∈ q, VTBL_VOLID ∈ vols, stat = used ∧ n0 < # apebs ∧ avhdr0.valid? ∧ avhdr0.vol = v ∧ avhdr0.leb = m0 ∧ n0 ≠ n

User applied rule all left

And obtained the following new goals

Proof step 20:
# wlar = # apebs, v × m0 ∈ recs0 ∧ recs0[v × m0].pnum = n0 ↔ wlar[n0].status = used ∧ n0 < # apebs ∧ apebs[n0].vidhdr.vol = (v × m0).vol ∧ apebs[n0].vidhdr.leb = (v × m0).leb, recs0[v × m0] = recovery-entry(n0, m3), apebs[n] = mkpeb(aehdr, avhdr, buf, m, boolvar), apebs[n0] = mkpeb(aehdr0, avhdr0, buf0, m1, boolvar0), wlar[n0] = wl-entry(m4, stat), bflipset-cons(bflipset, wlar), unique-sqns(apebs), unmapped-vols(vols), valid-eraseq(wlar, q), valid-eraseq-stronger(apebs, q), valid-vtbl(apebs, vols, wlar, n), valid-wl(apebs, wlar), v × m0 ∈ recs0 ⊦ v × m0 = VTBL_VOLID × VTBL_LNUM, VTBL_VOLID ∈ vols, n ∈ q, n0 ∈ q, stat = used ∧ n0 < # apebs ∧ avhdr0.valid? ∧ avhdr0.vol = v ∧ avhdr0.leb = m0 ∧ n0 ≠ n

Rule argument

pos: left 14 terms: v × m0, n0 abort: F discard: T computed: F

Additional information

Used terms: v × m0, n0