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Proof step 297 from proof prepost-scan-all (previous step)

# apebs = n1 + vtblpnum1, # wlar0 = n1 + vtblpnum1, apebs[vtblpnum1] = mkpeb(aechdr(m), avidhdr(v, m1, m2, m3, checksum(buf1, m3)), buf1, m0, false), valid-sqns(v, m1, apebs, vtblpnum1) = ∅, nx < vtblpnum1, bflipset-cons(bflipset, subarray(wlar0, 0, vtblpnum1)), indices-erasing(wlar0, nx), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aechdr(m), avidhdr(v, m1, m2, m3, checksum(buf1, m3)), buf1, m0, false)), unique-sqns(apebs), valid-eraseq(subarray(wlar0, 0, vtblpnum1), q), valid-eraseq-stronger(subarray(apebs, 0, vtblpnum1), q), valid-global-sqn(subarray(apebs, 0, vtblpnum1), sqnum), valid-recs(subarray(apebs, 0, vtblpnum1), subarray(wlar0, 0, vtblpnum1), recs), valid-recs-sqns(apebs, recs), valid-wl(subarray(apebs, 0, vtblpnum1), subarray(wlar0, 0, vtblpnum1)), m3 ≤ LEB_SIZE, m3 ≤ datasize(buf1) ⊦ m3 = 0, n1 = 0, dups(nx), v × m1 ∈ recs, ∃ m4, m5, m6. avidhdr(v, m1, m2, m3, checksum(buf1, m3)) = avidhdr(v, m1, m4, m5, m6) ∧ (m5 ≠ 0 → m5 ≤ datasize(buf1) ∧ m6 = checksum(buf1, m5)), valid-global-sqn(subarray(apebs, 0, vtblpnum1 + 1), max(sqnum, m2 + 1)) ∧ valid-wl(subarray(apebs, 0, vtblpnum1 + 1), subarray(wlar0[vtblpnum1, wl-entry(m, used)], 0, vtblpnum1 + 1)) ∧ valid-recs-sqns(apebs, recs[v × m1, recovery-entry(vtblpnum1, m2)])

User applied rule exists right

And closed the goal!

Rule argument

pos: right 5 terms: m2, m3, checksum(buf1, m3) abort: F discard: T computed: T

Additional information

Used terms: m2, m3, checksum(buf1, m3)