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Proof step 43 from proof prepost-scan-all (previous step)

# apebs = n0 + vtblpnum, # wlar = n0 + vtblpnum, err = err0, err = ESUCCESS, vtblpnum0 = vtblpnum, apebs[vtblpnum].bad, vtblpnum0 < # wlar, vtblpnum < # apebs, nx < vtblpnum, bflipset-cons(bflipset, subarray(wlar, 0, vtblpnum)), indices-erasing(wlar, nx), ubi-io-inv(apebs), unique-sqns(apebs), valid-eraseq(subarray(wlar, 0, vtblpnum), q), valid-eraseq-stronger(subarray(apebs, 0, vtblpnum), q), valid-global-sqn(subarray(apebs, 0, vtblpnum), sqnum), valid-recs(subarray(apebs, 0, vtblpnum), subarray(wlar, 0, vtblpnum), recs), valid-recs-sqns(apebs, recs), valid-wl(subarray(apebs, 0, vtblpnum), subarray(wlar, 0, vtblpnum)), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪vtblpnum := vtblpnum0 + 1⟫ ( vtblpnum ≤ # apebs ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ ( err = ESUCCESS → # apebs = # wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)] ∧ ¬ dups(nx) ∧ nx < vtblpnum ∧ indices-erasing(wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)], nx) ∧ valid-global-sqn(subarray(apebs, 0, vtblpnum), sqnum) ∧ valid-eraseq(subarray(wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)], 0, vtblpnum), q) ∧ bflipset-cons(bflipset, subarray(wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)], 0, vtblpnum)) ∧ valid-eraseq-stronger(subarray(apebs, 0, vtblpnum), q) ∧ valid-wl(subarray(apebs, 0, vtblpnum), subarray(wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)], 0, vtblpnum)) ∧ valid-recs-sqns(apebs, recs) ∧ valid-recs(subarray(apebs, 0, vtblpnum), subarray(wlar[vtblpnum0, wl-entry(wlar[vtblpnum0].ec, erroneous)], 0, vtblpnum), recs)) ∧ # apebs < n0 + vtblpnum), n0 = 0, dups(nx)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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