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Proof step 12 from proof prepost-wl-free-max-below (previous step)

wlar[m3].status = free, ¬ boolvar ↔ below(free-ecs(wlar, m3), n) = ∅, wlar[m0] = wl-entry(m1, free), wlar[m3].ec < n, m3 < # wlar, m1 < n, m0 < # wlar, boolvar → vtblpnum < # wlar ∧ wlar[vtblpnum].status = free ∧ wlar[vtblpnum].ec = below(free-ecs(wlar, m3), n).max, boolvar → vtblpnum < # wlar, ¬ boolvar ∨ wlar[vtblpnum].ec < wlar[m3].ec ⊦ wlar[m3].ec = below(free-ecs(wlar, m3 + 1), n).max ∧ below(free-ecs(wlar, m3 + 1), n) ≠ ∅

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 13:
wlar[m3].status = free, ¬ boolvar ↔ below(free-ecs(wlar, m3), n) = ∅, wlar[m0] = wl-entry(m1, free), wlar[vtblpnum] = wl-entry(m, stat), m0 < # wlar, m1 < n, m3 < # wlar, wlar[m3].ec < n, boolvar → vtblpnum < # wlar, boolvar → vtblpnum < # wlar ∧ stat = free ∧ m = below(free-ecs(wlar, m3), n).max, ¬ boolvar ∨ m < wlar[m3].ec ⊦ wlar[m3].ec = below(free-ecs(wlar, m3 + 1), n).max ∧ below(free-ecs(wlar, m3 + 1), n) ≠ ∅

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[vtblpnum], m, stat]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[vtblpnum], m, stat