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Proof step 2 from proof prepost-wl-free-max-below (previous step)

wlar[m0].status = free, wlar[m0].ec < n, m0 < # wlar ⊦ ⟪ubi_wl_find_free_max_below#(n, wlar; m)⟫ (m < # wlar ∧ wlar[m].status = free ∧ wlar[m].ec = below(free-ecs(wlar), n).max)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
wlar[m0] = wl-entry(m1, stat), stat = free, m0 < # wlar, m1 < n ⊦ ⟪ubi_wl_find_free_max_below#(n, wlar; m)⟫ (m < # wlar ∧ wlar[m].status = free ∧ wlar[m].ec = below(free-ecs(wlar), n).max)

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[m0], m1, stat]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[m0], m1, stat