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Proof step 3 from proof ubi-is-max-unique (previous step)

is-max(apebs, vols1, wlar1, q1, bflipset1, m0, m1), is-max(apebs, vols0, wlar0, q0, bflipset0, n0, n1) ⊦ vols0 = vols1

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
⊦ is-max(apebs, vols0, wlar0, q0, bflipset0, n0, n1) ∧ ubi-cons(apebs, vols1, wlar1, q1, bflipset1, m0, m1) → vols1 ⊆ vols0
Proof step 5:
is-max(apebs, vols0, wlar0, q0, bflipset0, n0, n1), is-max(apebs, vols1, wlar1, q1, bflipset1, m0, m1), is-max(apebs, vols0, wlar0, q0, bflipset0, n0, n1) ∧ ubi-cons(apebs, vols1, wlar1, q1, bflipset1, m0, m1) → vols1 ⊆ vols0 ⊦ vols0 = vols1

Rule argument

spec: ubi-crash-recovery-base name: vols-is-max-is-max-vols seq: ⊦ is-max(apebs, vols0, wlar0, q0, bflipset0, n0, n1) ∧ ubi-cons(apebs, vols1, wlar1, q1, bflipset1, m0, m1) → vols1 ⊆ vols0 subst: [apebs, vols0, wlar0, q0, bflipset0, n0, n1, vols1, wlar1, q1, bflipset1, m0, m1] → [apebs, vols0, wlar0, q0, bflipset0, n0, n1, vols1, wlar1, q1, bflipset1, m0, m1]

Additional information

Used terms: apebs, vols0, wlar0, q0, bflipset0, n0, n1, vols1, wlar1, q1, bflipset1, m0, m1