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Proof step 10 from proof bitflip-cons-set (previous step)

wlar[n] = wl-entry(m1, stat0), wlar[m, wl-entry(m0, stat)][n] = wl-entry(m2, stat1), n ∈ bflipset → n < # wlar ∧ stat1 = used, ∀ n. n ∈ bflipset → n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = used ⊦ stat = used, (n ∈ bflipset → n < # wlar ∧ stat0 = used) ∧ ¬ m ∈ bflipset

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 11:
wlar[m, wl-entry(m0, stat)][n] = wl-entry(m2, stat1), wlar[n] = wl-entry(m1, stat0), n ∈ bflipset → n < # wlar ∧ stat1 = used, ∀ n. n ∈ bflipset → n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = used ⊦ n = m, stat = used, (n ∈ bflipset → n < # wlar ∧ stat0 = used) ∧ ¬ m ∈ bflipset

Rule argument

fma: n = m

Additional information

Used simplifier rules: ⊦ m < # wlar → wlar[m, wle][m] = wle; (s)% ⊦ wl-entry(m, stat) = wl-entry(m0, stat0) ↔ m = m0 ∧ stat = stat0; (ws) Used formulas: n = m