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Proof step 2 from proof bitflip-cons-set (previous step)

⊦ wle.status = used, bflipset-cons(bflipset, wlar[m, wle]) ↔ bflipset-cons(bflipset, wlar) ∧ ¬ m ∈ bflipset

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ wle.status = used, (∀ n. n ∈ bflipset → n < # wlar ∧ wlar[m, wle][n].status = used) ↔ (∀ n. n ∈ bflipset → n < # wlar ∧ wlar[n].status = used) ∧ ¬ m ∈ bflipset

Rule argument

Additional information

Used simplifier rules: bflipset-cons: ⊦ bflipset-cons(bflipset, wlar) ↔ (∀ n. n ∈ bflipset → n < # wlar ∧ wlar[n].status = used);% ⊦ # wlar[n, wle] = # wlar; (s)