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Proof step 8 from proof bitflip-cons-set (previous step)

wlar[n] = wl-entry(m1, stat0), ∀ n. n ∈ bflipset → n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = used ⊦ stat = used, (n ∈ bflipset → n < # wlar ∧ stat0 = used) ∧ ¬ m ∈ bflipset

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 9:
wlar[n] = wl-entry(m1, stat0), n ∈ bflipset → n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = used, ∀ n. n ∈ bflipset → n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = used ⊦ stat = used, (n ∈ bflipset → n < # wlar ∧ stat0 = used) ∧ ¬ m ∈ bflipset

Rule argument

pos: left 2 terms: n

Additional information

Used terms: n