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Proof step 2 from proof bitflips-cons-in (previous step)

wlar[n] = wl-entry(m, stat), bflipset-cons(bflipset, wlar), n ∈ bflipset ⊦ stat = used

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
wlar[n] = wl-entry(m, stat), n ∈ bflipset, ∀ n. n ∈ bflipset → n < # wlar ∧ wlar[n].status = used ⊦ # bflipset = 0, bflipset = ∅, stat = used

Rule argument

Additional information

Used simplifier rules: bflipset-cons: ⊦ bflipset-cons(bflipset, wlar) ↔ (∀ n. n ∈ bflipset → n < # wlar ∧ wlar[n].status = used);%size-zero-01: ⊦ ns ≠ ∅ → # ns ≠ 0; (forward) from specification set-basic[nat-set]%ne-01: ⊦ n ∈ ns → ns ≠ ∅; (forward) from specification set-basic[nat-set]