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Proof step 1 from proof idset-trans-intersect (conclusion)
⊦ id(apebs2, apebs1, ns0) ∧ id(apebs1, apebs0, ns1) → id(apebs2, apebs0, ns0 ∩ ns1)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
id(apebs2, apebs1, ns0), id(apebs1, apebs0, ns1) ⊦ id(apebs2, apebs0, ns0 ∩ ns1)
Rule argument
Additional information