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Proof step 3 from proof idset-weaken (previous step)

# apebs1 = # apebs0, n0 < # apebs0, n0 ∈ ns, ∀ n1. n1 ∈ ns ∧ n1 < # apebs0 → apebs1[n1] = apebs0[n1] ⊦ # ns = 0, apebs1[n0] = apebs0[n0], n0 = n, ns = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: n0

Additional information

Used terms: n0