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Proof step 15 from proof in-valid-eraseqp-valid-lref (previous step)

apebs[m0] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m0 < # apebs, valid-eraseq(apebs, q0), valid-peb(v, m, apebs[n]), ∀ apebs, v, m, n, lref. valid-eraseq(apebs, q0) ∧ valid-peb(v, m, apebs[n]) ∧ eq-entry(n, lref) ∈ q0 → lref = v × m, eq-entry(n, lref) = eq-entry(m0, lref0) ∨ eq-entry(n, lref) ∈ q0 ⊦ lref = v × m, valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar))

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 16:
apebs[m0] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m0 < # apebs, valid-eraseq(apebs, q0), valid-peb(v, m, apebs[n]), ∀ apebs, v, m, n, lref. valid-eraseq(apebs, q0) ∧ valid-peb(v, m, apebs[n]) ∧ eq-entry(n, lref) ∈ q0 → lref = v × m, eq-entry(n, lref) = eq-entry(m0, lref0) ∨ eq-entry(n, lref) ∈ q0 ⊦ eq-entry(n, lref) = eq-entry(m0, lref0), lref = v × m, valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar))

Rule argument

fma: eq-entry(n, lref) = eq-entry(m0, lref0)

Additional information

Used simplifier rules: ⊦ eq-entry(m, lref) = eq-entry(m0, lref0) ↔ m = m0 ∧ lref = lref0; (ws)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic% ⊦ valid-peb(v, m, apeb) → valid-peb(apeb); (ss) Used formulas: eq-entry(n, lref) = eq-entry(m0, lref0)