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Proof step 17 from proof in-valid-eraseqp-valid-lref (previous step)

apebs[m0] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m0 < # apebs, valid-eraseq(apebs, q0), valid-peb(v, m, apebs[n]), eq-entry(n, lref) ∈ q0, ∀ apebs, v, m, n, lref. valid-eraseq(apebs, q0) ∧ valid-peb(v, m, apebs[n]) ∧ eq-entry(n, lref) ∈ q0 → lref = v × m ⊦ eq-entry(n, lref) = eq-entry(m0, lref0), lref = v × m, valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar))

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: apebs, v, m, n, lref

Additional information

Used simplifier rules: ⊦ valid-peb(v0, m0, apeb) → (valid-peb(v1, m1, apeb) ↔ v0 = v1 ∧ m0 = m1); (s) Used terms: apebs, v, m, n, lref