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Proof step 12 from proof mapped-pebs-add-empty-vol (previous step)

vols[v0][m] = ⌜n0⌝ , m < # vols[v0], v0 ∈ vols ⊦ v ∈ vols, ∃ v0, m. v0 ∈ vols[v, fill(mkebatbl(n), unmapped)] ∧ m < # vols[v, fill(mkebatbl(n), unmapped)][v0] ∧ vols[v, fill(mkebatbl(n), unmapped)][v0][m] = ⌜n0⌝

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: v0, m abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ v ∈ vols ∧ ¬ v0 ∈ vols → vols[v0, ebatbl][v] = vols[v]; (s)% ⊦ v ∈ vols[v0, ebatbl] ↔ v = v0 ∨ v ∈ vols; (ws) Used terms: v0, m