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Proof step 26 from proof mapped-pebs-remap (previous step)

vols[v0][m1] = ⌜n0⌝ , vols[v][m] = ⌜n0⌝ , m1 < # vols[v0], m < # vols[v], v0 ∈ vols, v ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ m0 ⊦ n0 = n1, v0 = v

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 27:
vols[v0][m1] = ⌜n0⌝ ∧ v0 ∈ vols ∧ m1 < # vols[v0] ↔ wlar[n0].status = used ∧ n0 < # apebs ∧ n0 < # wlar ∧ apebs[n0].vidhdr.valid? ∧ apebs[n0].vidhdr.vol = v0 ∧ apebs[n0].vidhdr.leb = m1 ∧ n0 ≠ m0, vols[v][m] = ⌜n0⌝ , vols[v0][m1] = ⌜n0⌝ , m < # vols[v], m1 < # vols[v0], v ∈ vols, v0 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ m0 ⊦ n0 = n1, v0 = v

Rule argument

pos: left 7 terms: v0, m1, n0

Additional information

Used terms: v0, m1, n0