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Proof step 10 from proof unique-sqns-2-valid-pebs (previous step)

avhdr.sqn = avhdr0.sqn, apebs[m0] = mkpeb(aehdr, avhdr, buf, m2, boolvar), apebs[m1] = mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0), valid-sqns(v, m, apebs) = bag ++ avhdr0.sqn ++ avhdr0.sqn, m1 < # apebs, m0 < # apebs, valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0)), valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m2, boolvar)), ∀ v, m. unique-elems(valid-sqns(v, m, apebs)) ⊦ m0 = m1

User applied rule all left

And closed the goal!

Rule argument

pos: left 9 terms: v, m abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ unique-elems(bag0) → bag0 ≠ bag1 ++ n ++ n; (s) Used terms: v, m