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Proof step 24 from proof unique-sqns-write-valid (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf0, m0, boolvar0), m < # apebs, valid-peb(mkpeb(aehdr, avhdr, buf1, m1, boolvar1)), valid-peb(mkpeb(aehdr, avhdr, buf0, m0, boolvar0)), ∀ v, m. unique-elems(valid-sqns(v, m, apebs)) ⊦ unique-elems(valid-sqns(v, m2, apebs)), v = avhdr.vol ∧ m2 = avhdr.leb

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: v, m2

Additional information

Used terms: v, m2