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Proof step 37 from proof valid-ebatbl-add-unmapped-vol (previous step)

wlar[n1] = wl-entry(m2, free), apebs[n2] = mkpeb(aehdr, avidhdr(v0, m5, m6, m7, m8), buf, m3, boolvar), wlar[n2] = wl-entry(m4, used), n2 < # apebs, n2 < # wlar, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n2 = n0, n2 = n1, v0 = v, v ∈ vols, vols[v0][m5] = ⌜n2⌝ ∧ v0 ∈ vols ∧ m5 < # vols[v0]

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: v0, m5, n2

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).vidhdr = avhdr; (s)% ⊦ avidhdr(v, m, m0, m1, m2).valid?; (s)% ⊦ avidhdr(v, m, m0, m1, m2).vol = v; (s)% ⊦ avidhdr(v, m, m0, m1, m2).leb = m; (s) Used terms: v0, m5, n2