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Proof step 5 from proof valid-ebatbl-add-unmapped-vol (previous step)

apebs[n2] = mkpeb(aehdr, avhdr, buf, m3, boolvar), wlar[n1] = wl-entry(m2, free), wlar[n1, wl-entry(m1, used)][n0, wl-entry(m0, erasing)][n2] = wl-entry(m4, stat), ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ vols[v, fill(mkebatbl(n), unmapped)][v0][m] = ⌜n2⌝ ∧ v0 ∈ vols[v, fill(mkebatbl(n), unmapped)] ∧ m < # vols[v, fill(mkebatbl(n), unmapped)][v0] ↔ stat = used ∧ n2 < # apebs ∧ n2 < # wlar ∧ avhdr.valid? ∧ avhdr.vol = v0 ∧ avhdr.leb = m ∧ n2 ≠ n1, v ∈ vols

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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