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Proof step 55 from proof valid-ebatbl-remap (previous step)

vols[v0][m0] = ⌜n1⌝ ∧ v0 ∈ vols ∧ m0 < # vols[v0] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v0 ∧ apebs[n1].vidhdr.leb = m0 ∧ n1 ≠ n0, vols[v0][m0] = ⌜n1⌝ , apebs[n] = mkpeb(aehdr, avidhdr(v0, m0, m3, m4, m5), buf, m6, boolvar), apebs[n2] = mkpeb(aehdr0, avidhdr(v0, m0, m1, m2, m10), buf0, m7, boolvar0), wlar[n] = wl-entry(m9, stat0), wlar[n2] = wl-entry(m8, used), n < # apebs, n < # wlar, n2 < # apebs, n2 < # wlar, m0 < # vols[v0], v0 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n = n0, n1 = n0, n2 = n, n2 = n1, n2 = n0, stat0 = used

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic