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Proof step 10 from proof valid-ebatbl-unmap (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m3, boolvar), vols[v][m] = ⌜n⌝ , vols[v, vols[v][m, unmapped]][v0][m1] = ⌜n⌝ , v0 = v, m < # vols[v], n < # wlar, m1 < # vols[v, vols[v][m, unmapped]][v0], v ∈ vols, v0 ∈ vols[v, vols[v][m, unmapped]], ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
vols[v][m] = ⌜n⌝ , apebs[n] = mkpeb(aehdr, avhdr, buf, m3, boolvar), vols[v][m, unmapped][m1] = ⌜n⌝ , n < # wlar, m < # vols[v], m1 < # vols[v], v ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ # ebatbl[n, ebae] = # ebatbl; (s)% ⊦ v ∈ vols[v, ebatbl]; (s)% ⊦ vols[v, ebatbl][v] = ebatbl; (s)