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Proof step 25 from proof valid-ebatbl-unmap (previous step)

wlar[n].status = used, apebs[n] = mkpeb(aehdr, avidhdr(v1, m0, m2, m4, m5), buf, m3, boolvar), vols[v0][m1] = ⌜n⌝ , vols[v1][m0] = ⌜n⌝ , m0 < # vols[v1], n < # apebs, n < # wlar, m1 < # vols[v0], v0 ∈ vols, v1 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n = n0, v0 = v1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 26:
vols[v1][m0] = ⌜n⌝ , vols[v0][m1] = ⌜n⌝ , apebs[n] = mkpeb(aehdr, avidhdr(v1, m0, m2, m4, m5), buf, m3, boolvar), wlar[n] = wl-entry(m6, stat), stat = used, m1 < # vols[v0], n < # wlar, n < # apebs, m0 < # vols[v1], v1 ∈ vols, v0 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n = n0, v0 = v1

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[n], m6, stat]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[n], m6, stat