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Proof step 39 from proof valid-ebatbl-unmap (previous step)

wlar[n1] = wl-entry(m2, used), apebs[n1] = mkpeb(aehdr, avidhdr(v0, m0, m1, m4, m5), buf, m3, boolvar), vols[v0][m0] = ⌜n⌝ , m0 < # vols[v0], n1 < # wlar, n1 < # apebs, v0 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n1 = n0, n1 = n

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 40:
vols[v0][m0] = ⌜n⌝ ∧ v0 ∈ vols ∧ m0 < # vols[v0] ↔ wlar[n].status = used ∧ n < # apebs ∧ n < # wlar ∧ apebs[n].vidhdr.valid? ∧ apebs[n].vidhdr.vol = v0 ∧ apebs[n].vidhdr.leb = m0 ∧ n ≠ n0, vols[v0][m0] = ⌜n⌝ , apebs[n1] = mkpeb(aehdr, avidhdr(v0, m0, m1, m4, m5), buf, m3, boolvar), wlar[n1] = wl-entry(m2, used), n1 < # apebs, n1 < # wlar, m0 < # vols[v0], v0 ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ n1 = n, n1 = n0

Rule argument

pos: left 8 terms: v0, m0, n

Additional information

Used terms: v0, m0, n