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Proof step 50 from proof valid-ebatbl-unmap (previous step)

wlar[n1] = wl-entry(m2, stat), apebs[n1] = mkpeb(aehdr, avhdr, buf, m3, boolvar), vols[v][m] = ⌜n⌝ , m < # vols[v], v ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ vols[v][m, unmapped][m1] = ⌜n1⌝ ∧ m1 < # vols[v] ↔ stat = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ avhdr.valid? ∧ avhdr.vol = v ∧ avhdr.leb = m1 ∧ n1 ≠ n0, m1 = m, n1 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
vols[v][m] = ⌜n⌝ , apebs[n1] = mkpeb(aehdr, avhdr, buf, m3, boolvar), wlar[n1] = wl-entry(m2, stat), m < # vols[v], v ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ vols[v][m1] = ⌜n1⌝ ∧ m1 < # vols[v] ↔ stat = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ avhdr.valid? ∧ avhdr.vol = v ∧ avhdr.leb = m1 ∧ n1 ≠ n0, m1 = m, n1 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m ≠ n → ebatbl[n, ebae][m] = ebatbl[m]; (s)