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Proof step 53 from proof valid-ebatbl-unmap (previous step)

vols[v][m] = ⌜n⌝ , apebs[n1] = mkpeb(aehdr, avhdr, buf, m3, boolvar), wlar[n1] = wl-entry(m2, stat), m < # vols[v], v ∈ vols, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0 ⊦ vols[v0][m1] = ⌜n1⌝ ∧ v0 ∈ vols ∧ m1 < # vols[v0] ↔ stat = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ avhdr.valid? ∧ avhdr.vol = v0 ∧ avhdr.leb = m1 ∧ n1 ≠ n0, n1 = n, v0 = v

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: v0, m1, n1

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).vidhdr = avhdr; (s) Used terms: v0, m1, n1