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Proof step 4 from proof valid-ebatbl-update-wlar-unused (previous step)

wlar[m] = wl-entry(m0, stat), ∀ v, m2, n0. vols[v][m2] = ⌜n0⌝ ∧ v ∈ vols ∧ m2 < # vols[v] ↔ wlar[m, wl-entry(m1, stat0)][n0].status = used ∧ n0 < # apebs ∧ n0 < # wlar ∧ apebs[n0].vidhdr.valid? ∧ apebs[n0].vidhdr.vol = v ∧ apebs[n0].vidhdr.leb = m2 ∧ n0 ≠ n ⊦ stat = used, stat0 = used, ∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
wlar[m] = wl-entry(m0, stat), ∀ v, m2, n0. vols[v][m2] = ⌜n0⌝ ∧ v ∈ vols ∧ m2 < # vols[v] ↔ wlar[m, wl-entry(m1, stat0)][n0].status = used ∧ n0 < # apebs ∧ n0 < # wlar ∧ apebs[n0].vidhdr.valid? ∧ apebs[n0].vidhdr.vol = v ∧ apebs[n0].vidhdr.leb = m2 ∧ n0 ≠ n ⊦ vols[v][m2] = ⌜n0⌝ ∧ v ∈ vols ∧ m2 < # vols[v] ↔ wlar[n0].status = used ∧ n0 < # apebs ∧ n0 < # wlar ∧ apebs[n0].vidhdr.valid? ∧ apebs[n0].vidhdr.vol = v ∧ apebs[n0].vidhdr.leb = m2 ∧ n0 ≠ n, stat = used, stat0 = used

Proof step 4 from proof valid-ebatbl-update-wlar-unused (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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