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Proof step 2 from proof valid-ebatbl-write-data (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf0, m0, boolvar) ⊦ valid-ebatbl(apebs[n, mkpeb(aehdr, avhdr, buf1, m1, boolvar)], wlar, vols, n0) ↔ valid-ebatbl(apebs, wlar, vols, n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
apebs[n] = mkpeb(aehdr, avhdr, buf0, m0, boolvar) ⊦ (∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n, mkpeb(aehdr, avhdr, buf1, m1, boolvar)][n1].vidhdr.valid? ∧ apebs[n, mkpeb(aehdr, avhdr, buf1, m1, boolvar)][n1].vidhdr.vol = v ∧ apebs[n, mkpeb(aehdr, avhdr, buf1, m1, boolvar)][n1].vidhdr.leb = m ∧ n1 ≠ n0) ↔ (∀ v, m, n1. vols[v][m] = ⌜n1⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n1].status = used ∧ n1 < # apebs ∧ n1 < # wlar ∧ apebs[n1].vidhdr.valid? ∧ apebs[n1].vidhdr.vol = v ∧ apebs[n1].vidhdr.leb = m ∧ n1 ≠ n0)

Rule argument

Additional information

Used simplifier rules: valid-ebatbl: ⊦ valid-ebatbl(apebs, wlar, vols, n0) ↔ (∀ v, m, n. vols[v][m] = ⌜n⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n].status = used ∧ n < # apebs ∧ n < # wlar ∧ apebs[n].vidhdr.valid? ∧ apebs[n].vidhdr.vol = v ∧ apebs[n].vidhdr.leb = m ∧ n ≠ n0);% ⊦ # apebs[n, apeb] = # apebs; (s)