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Proof step 12 from proof valid-eraseqd-append (previous step)

valid-eraseq(q0), valid-eraseq(q0 + eq-entry(m, lref) '), m ∈ q0, ∀ m1, lref1. valid-eraseq(q0 + eq-entry(m1, lref1) ') ↔ ¬ m1 ∈ q0 ⊦ m0 ∈ q0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: m, lref

Additional information

Used terms: m, lref