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Proof step 16 from proof valid-eraseqd-append (previous step)

valid-eraseq(q0 + eq-entry(m, lref) '), ∀ m1, lref0. ¬ valid-eraseq(q0 + eq-entry(m1, lref0) ') ⊦ m0 = m, valid-eraseq(q0), m0 ∈ q0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m, lref

Additional information

Used terms: m, lref