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Proof step 6 from proof valid-eraseqd-nodups-middle1 (previous step)

eqent = eq-entry(m1, lref1), valid-eraseq(q + eq-entry(m, lref) ' + q1), m ∈ q1, ∀ m0, lref0, q0. ¬ valid-eraseq(q + eq-entry(m0, lref0) ' + q0) ∨ ¬ m0 ∈ q0 ⊦ m1 ∈ q1, m1 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
valid-eraseq(q + eq-entry(m, lref) ' + q1), m ∈ q1, ∀ m0, lref0, q0. ¬ valid-eraseq(q + eq-entry(m0, lref0) ' + q0) ∨ ¬ m0 ∈ q0 ⊦ m1 ∈ q, m1 ∈ q1

Proof step 6 from proof valid-eraseqd-nodups-middle1 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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