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Proof step 7 from proof valid-eraseqd-nodups-middle2 (previous step)

valid-eraseq(q + eq-entry(m, lref) ' + q1), m ∈ q + q1, ∀ m0, lref0, q0. ¬ valid-eraseq(q + eq-entry(m0, lref0) ' + q0) ∨ ¬ m0 ∈ q + q0 ⊦ m1 = m, m1 ∈ q, m1 ∈ q1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m, lref, q1

Additional information

Used simplifier rules: a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base] Used terms: m, lref, q1