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Proof step 2 from proof valid-eraseqd-nodups0 (previous step)

valid-eraseq(q0 + q1), m ∈ q1, m ∈ q0 ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: valid-eraseqd-nodups1: ⊦ valid-eraseq(q0 + q1) ∧ m ∈ q1 → ¬ m ∈ q0;%a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base]