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Proof step 20 from proof valid-eraseqp-invalidate (previous step)

apebs[m0] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), m0 < # apebs, m < # apebs, valid-eraseq(apebs, q0), ∀ m, apebs, apeb. m < # apebs ∧ valid-eraseq(apebs, q0) → valid-eraseq(apebs[m, apeb], q0) ∨ valid-peb(apeb) ⊦ m0 = m, valid-eraseq(apebs[m, apeb], q0), valid-peb(apeb)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: m, apebs, apeb

Additional information

Used terms: m, apebs, apeb