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Proof step 5 from proof valid-eraseqp-rem-middle (previous step)

eqent0.pnum < # apebs, valid-eraseq(apebs, q + eqent ' + q1), valid-peb(apebs[eqent0.pnum]) → eqent0.lebref = apebs[eqent0.pnum].vidhdr.vol × apebs[eqent0.pnum].vidhdr.leb, ∀ apebs, eqent, q1. valid-eraseq(apebs, q + eqent ' + q1) → valid-eraseq(apebs, q + q1) ⊦ valid-eraseq(apebs, q + q1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
eqent0 = eq-entry(m, lref), m < # apebs, valid-eraseq(apebs, q + eqent ' + q1), valid-peb(apebs[m]) → lref = apebs[m].vidhdr.vol × apebs[m].vidhdr.leb, ∀ apebs, eqent, q1. valid-eraseq(apebs, q + eqent ' + q1) → valid-eraseq(apebs, q + q1) ⊦ valid-eraseq(apebs, q + q1)

Rule argument

spec: erasequeueentry name: elim seq: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref) subst: [eqent, m, lref] → [eqent0, m, lref]

Additional information

Used simplifier rules: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref); (elim) Used terms: eqent0, m, lref