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Proof step 2 from proof valid-eraseqp-valid-lebref (
previous step
)
valid-eraseq(apebs, q), valid-peb(v, m, apebs[n]), n ∈ q ⊦ eq-entry(n, v × m) ∈ q
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
valid-eraseq(apebs, q), valid-peb(v, m, apebs[n]), n ∈ q ⊦ eq-entry(n, v × m) ∈ q
Rule argument
Additional information