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Proof step 1 from proof valid-eraseqw-free (conclusion)

stat ≠ erasing ⊦ valid-eraseq(wlar, q0 + eq-entry(m, lref) ' + q1) → (valid-eraseq(wlar[m, wl-entry(m0, stat)], q0 + q1) ↔ ¬ m ∈ q0 ∧ ¬ m ∈ q1)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information