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Proof step 12 from proof valid-eraseqw-free (previous step)

n ∈ q0 ∨ n ∈ eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ stat1 = erasing, wlar[n] = wl-entry(m2, stat1), wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0) ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q0, m ∈ q1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
n ∈ q0 ∨ n ∈ eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ stat1 = erasing, wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0), wlar[n] = wl-entry(m2, stat1) ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q1, m ∈ q0

Proof step 12 from proof valid-eraseqw-free (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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