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Proof step 16 from proof valid-eraseqw-free (previous step)

n ∈ q0 ∨ n = m ∨ n ∈ q1 ↔ n < # wlar ∧ stat1 = erasing, wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0), wlar[n] = wl-entry(m2, stat1) ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q1, m ∈ q0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ n ∈ q0 + q1 ↔ n ∈ q0 ∨ n ∈ q1
Proof step 18:
n ∈ q0 ∨ n = m ∨ n ∈ q1 ↔ n < # wlar ∧ stat1 = erasing, wlar[n] = wl-entry(m2, stat1), wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0) ⊦ n ∈ q0 ∨ n ∈ q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q0, m ∈ q1

Rule argument

spec: erasequeue name: in-concat seq: ⊦ n ∈ q0 + q1 ↔ n ∈ q0 ∨ n ∈ q1 subst: [q1, q0, n] → [q1, q0, n] flags: <all paths>

Additional information

Used terms: q1, q0, n