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Proof step 19 from proof valid-eraseqw-free (previous step)

n ∈ q0 ∨ n = m ∨ n ∈ q1 ↔ n < # wlar ∧ stat1 = erasing, wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0), wlar[n] = wl-entry(m2, stat1) ⊦ n ∈ q0 ∨ n ∈ q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q1, m ∈ q0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: n = m

Additional information

Used simplifier rules: ⊦ m ≠ n → wlar[n, wle][m] = wlar[m]; (s)% ⊦ wl-entry(m, stat) = wl-entry(m0, stat0) ↔ m = m0 ∧ stat = stat0; (ws)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n < m ↔ false); (s)%m < # wlar ⊦ wlar[m, wle][m] = wle; (s) Used formulas: n = m