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Proof step 4 from proof valid-eraseqw-free (previous step)

∀ n. n ∈ q0 + eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ wlar[n].status = erasing, ∀ n. n ∈ q0 + q1 ↔ n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = erasing ⊦ stat = erasing, ¬ m ∈ q0 ∧ ¬ m ∈ q1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ n. n ∈ q0 + q1 ↔ n < # wlar ∧ wlar[m, wl-entry(m0, stat)][n].status = erasing, ∀ n. n ∈ q0 + eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ stat = erasing, ¬ m ∈ q0 ∧ ¬ m ∈ q1

Proof step 4 from proof valid-eraseqw-free (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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