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Proof step 11 from proof valid-eraseqw-subarray-shift (previous step)

wlar[n0] = wl-entry(m0, stat0), n < # wlar, n < n0, n0 ∈ q, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing, ¬ n < n0 ∧ stat0 = erasing

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
wlar[n0] = wl-entry(m0, stat0), n < # wlar, n < n0, n0 ∈ q, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic