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Proof step 15 from proof valid-eraseqw-subarray-shift (previous step)

wlar[n0] = wl-entry(m0, stat0), n < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 ∈ q ↔ ¬ n < n0 ∧ stat0 = erasing, n0 = n, stat = erasing, n0 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
wlar[n0] = wl-entry(m0, erasing), n0 < # wlar, n0 < n, n < # wlar, n0 + 1 < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing, n0 ∈ q

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)% ⊦ m < n → n ≠ 0; (s)%transitivity: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification oelem[nat-set]%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ n ≠ n0 → (n < n0 ↔ ¬ n0 < n); (ss)