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Proof step 3 from proof valid-eraseqw-subarray-shift (previous step)

n < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 ∈ q ↔ ¬ n < n0 ∧ wlar[n, wl-entry(m, stat)][n0].status = erasing, stat = erasing

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
wlar[n, wl-entry(m, stat)][n0] = wl-entry(m0, stat0), n < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 ∈ q ↔ ¬ n < n0 ∧ stat0 = erasing, stat = erasing

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[n, wl-entry(m, stat)][n0], m0, stat0]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[n, wl-entry(m, stat)][n0], m0, stat0