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Proof step 10 from proof valid-eraseqw-update-ec (previous step)

wlar[m] = wl-entry(m0, stat), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n ∈ q ↔ n < # wlar ∧ wlar[m, wl-entry(m1, stat)][n].status = erasing

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
wlar[m] = wl-entry(m0, stat), wlar[m, wl-entry(m1, stat)][n] = wl-entry(m2, stat0), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n ∈ q ↔ n < # wlar ∧ stat0 = erasing

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[m, wl-entry(m1, stat)][n], m2, stat0]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[m, wl-entry(m1, stat)][n], m2, stat0