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Proof step 1 from proof valid-eraseqw-use (conclusion)

stat ≠ erasing ⊦ wlar[n] = wl-entry(m0, stat) → (valid-eraseq(wlar[n, wl-entry(m1, used)], q) ↔ valid-eraseq(wlar, q))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information