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Proof step 20 from proof valid-global-sqn-add-valid (previous step)

apebs[m] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), avhdr.sqn < (valid-sqns(v, m0, apebs) -- avhdr0.sqn = ∅ ⊃ avhdr.sqn;(valid-sqns(v, m0, apebs) -- avhdr0.sqn).max), avhdr.sqn < (valid-sqns(v, m0, apebs) -- avhdr0.sqn).max, valid-sqns(v, m0, apebs).max < (valid-sqns(v, m0, apebs) -- avhdr0.sqn).max, avhdr.sqn < n, m < # apebs, valid-sqns(v, m0, apebs).max < n, valid-peb(v, m0, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar)), valid-peb(v, m0, mkpeb(aehdr, avhdr, buf, m1, boolvar)), n ≤ (valid-sqns(v, m0, apebs) -- avhdr0.sqn).max ⊦

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: valid-sqns(v, m0, apebs) -- avhdr0.sqn = ∅

Additional information

Used simplifier rules: ⊦ bag -- n ≠ ∅ → ¬ bag.max < (bag -- n).max; (s)% ⊦ ¬ n < n; (s) Used formulas: valid-sqns(v, m0, apebs) -- avhdr0.sqn = ∅