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Proof step 5 from proof valid-global-sqn-add-valid (previous step)

avhdr.sqn < valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]).max, avhdr.sqn < n, m < # apebs, valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar)), n ≤ valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]).max, ∀ v, m0. valid-sqns(v, m0, apebs) ≠ ∅ → valid-sqns(v, m0, apebs).max < n ⊦ valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]) = ∅

User applied rule all left

And obtained the following new goals

Proof step 6:
m < # apebs, avhdr.sqn < n, avhdr.sqn < valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]).max, valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar)), n ≤ valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]).max, valid-sqns(v, m0, apebs) ≠ ∅ → valid-sqns(v, m0, apebs).max < n ⊦ valid-sqns(v, m0, apebs[m, mkpeb(aehdr, avhdr, buf, m1, boolvar)]) = ∅

Rule argument

pos: left 6 terms: v, m0 abort: F discard: T computed: F

Additional information

Used terms: v, m0