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Proof step 3 from proof valid-global-sqn-invalidate (previous step)

m < # apebs, n ≤ valid-sqns(v, m0, apebs[m, apeb]).max, ∀ v, m0. valid-sqns(v, m0, apebs) ≠ ∅ → valid-sqns(v, m0, apebs).max < n ⊦ valid-sqns(v, m0, apebs[m, apeb]) = ∅, valid-peb(apeb)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: sqns name: valid-sqns-write seq: ⊦ n < # apebs → valid-sqns(v, m, apebs[n, apeb]) = ( valid-sqns(v, m, apebs) \ (valid-peb(v, m, apebs[n]) ⊃ {apebs[n].vidhdr.sqn} ;∅)) ∪ (valid-peb(v, m, apeb) ⊃ {apeb.vidhdr.sqn} ;∅) subst: [apeb, n, apebs, m, v] → [apeb, m, apebs, m0, v] flags: <all paths>

Additional information

Used terms: apeb, m, apebs, m0, v