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Proof step 8 from proof valid-global-sqn-invalidate (previous step)

m < # apebs, valid-peb(v, m0, apebs[m]), n ≤ (valid-sqns(v, m0, apebs) -- apebs[m].vidhdr.sqn).max, ∀ v, m0. valid-sqns(v, m0, apebs) ≠ ∅ → valid-sqns(v, m0, apebs).max < n ⊦ valid-sqns(v, m0, apebs) -- apebs[m].vidhdr.sqn = ∅, valid-peb(apeb)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
apebs[m] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m < # apebs, valid-peb(v, m0, apebs[m]), n ≤ (valid-sqns(v, m0, apebs) -- avhdr.sqn).max, ∀ v, m0. valid-sqns(v, m0, apebs) ≠ ∅ → valid-sqns(v, m0, apebs).max < n ⊦ valid-sqns(v, m0, apebs) -- avhdr.sqn = ∅, valid-peb(apeb)

Rule argument

spec: apeb name: elim seq: ⊦ ( ( (aehdr = apeb.echdr ∧ avhdr = apeb.vidhdr) ∧ buf = apeb.data) ∧ m = apeb.fill) ∧ (boolvar ↔ apeb.bad) ↔ apeb = mkpeb(aehdr, avhdr, buf, m, boolvar) subst: [apeb, aehdr, avhdr, buf, m, boolvar] → [apebs[m], aehdr, avhdr, buf, m2, boolvar]

Additional information

Used simplifier rules: ⊦ ( ((aehdr = apeb.echdr ∧ avhdr = apeb.vidhdr) ∧ buf = apeb.data) ∧ m = apeb.fill) ∧ (boolvar ↔ apeb.bad) ↔ apeb = mkpeb(aehdr, avhdr, buf, m, boolvar); (elim) Used terms: apebs[m], aehdr, avhdr, buf, m2, boolvar